Base | Representation |
---|---|
bin | 11011010011111000000100… |
… | …011100100101001101011011 |
3 | 120202021200222112211112211111 |
4 | 123103320010130211031123 |
5 | 111220413142240014433 |
6 | 1103243113221241151 |
7 | 34204613222264521 |
oct | 3323700434451533 |
9 | 522250875745744 |
10 | 120113130001243 |
11 | 352a97685a7605 |
12 | 1157a8902631b7 |
13 | 5203809227302 |
14 | 2193713c1a311 |
15 | dd4641420dcd |
hex | 6d3e0472535b |
120113130001243 has 2 divisors, whose sum is σ = 120113130001244. Its totient is φ = 120113130001242.
The previous prime is 120113130001237. The next prime is 120113130001331. The reversal of 120113130001243 is 342100031311021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120113130001243 - 217 = 120113129870171 is a prime.
It is not a weakly prime, because it can be changed into another prime (120113130001343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60056565000621 + 60056565000622.
It is an arithmetic number, because the mean of its divisors is an integer number (60056565000622).
Almost surely, 2120113130001243 is an apocalyptic number.
120113130001243 is a deficient number, since it is larger than the sum of its proper divisors (1).
120113130001243 is an equidigital number, since it uses as much as digits as its factorization.
120113130001243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 120113130001243 its reverse (342100031311021), we get a palindrome (462213161312264).
The spelling of 120113130001243 in words is "one hundred twenty trillion, one hundred thirteen billion, one hundred thirty million, one thousand, two hundred forty-three".
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