Base | Representation |
---|---|
bin | 10001011110101001000… |
… | …011000100110101000011 |
3 | 11020211022221211020222121 |
4 | 101132221003010311003 |
5 | 124134404300000144 |
6 | 2315443055545111 |
7 | 152531112544564 |
oct | 21365103046503 |
9 | 4224287736877 |
10 | 1201132031299 |
11 | 423440799a52 |
12 | 17495482b197 |
13 | 8935cca2105 |
14 | 421c6a0416b |
15 | 2139e29c384 |
hex | 117a90c4d43 |
1201132031299 has 2 divisors, whose sum is σ = 1201132031300. Its totient is φ = 1201132031298.
The previous prime is 1201132031261. The next prime is 1201132031371. The reversal of 1201132031299 is 9921302311021.
It is a weak prime.
It is an emirp because it is prime and its reverse (9921302311021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1201132031299 is a prime.
It is a super-2 number, since 2×12011320312992 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1201132031219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600566015649 + 600566015650.
It is an arithmetic number, because the mean of its divisors is an integer number (600566015650).
Almost surely, 21201132031299 is an apocalyptic number.
1201132031299 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201132031299 is an equidigital number, since it uses as much as digits as its factorization.
1201132031299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 34.
The spelling of 1201132031299 in words is "one trillion, two hundred one billion, one hundred thirty-two million, thirty-one thousand, two hundred ninety-nine".
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