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12011322113233 is a prime number
BaseRepresentation
bin1010111011001001101010…
…0101100111110011010001
31120112021022200122001022121
42232302122211213303101
53033243141430110413
641313531502134241
72346534521255002
oct256623245476321
946467280561277
1012011322113233
113910a78220083
12141ba5b581381
13691880288281
142d74cb57b1a9
1515c696ddab8d
hexaec9a967cd1

12011322113233 has 2 divisors, whose sum is σ = 12011322113234. Its totient is φ = 12011322113232.

The previous prime is 12011322113227. The next prime is 12011322113249. The reversal of 12011322113233 is 33231122311021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8869151084544 + 3142171028689 = 2978112^2 + 1772617^2 .

It is a cyclic number.

It is not a de Polignac number, because 12011322113233 - 217 = 12011321982161 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12011322113198 and 12011322113207.

It is not a weakly prime, because it can be changed into another prime (12011322113633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005661056616 + 6005661056617.

It is an arithmetic number, because the mean of its divisors is an integer number (6005661056617).

Almost surely, 212011322113233 is an apocalyptic number.

It is an amenable number.

12011322113233 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011322113233 is an equidigital number, since it uses as much as digits as its factorization.

12011322113233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12011322113233 its reverse (33231122311021), we get a palindrome (45242444424254).

The spelling of 12011322113233 in words is "twelve trillion, eleven billion, three hundred twenty-two million, one hundred thirteen thousand, two hundred thirty-three".