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120115106497 is a prime number
BaseRepresentation
bin110111111011101101…
…0110001001011000001
3102111001000202121221001
41233313122301023001
53431443431401442
6131102523332001
711451364362601
oct1576732611301
9374030677831
10120115106497
1146a38934361
121b342381001
13b432cb9b19
145b5674ac01
1531d01412b7
hex1bf76b12c1

120115106497 has 2 divisors, whose sum is σ = 120115106498. Its totient is φ = 120115106496.

The previous prime is 120115106479. The next prime is 120115106533. The reversal of 120115106497 is 794601511021.

Together with previous prime (120115106479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96471738801 + 23643367696 = 310599^2 + 153764^2 .

It is a cyclic number.

It is not a de Polignac number, because 120115106497 - 211 = 120115104449 is a prime.

It is a super-2 number, since 2×1201151064972 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120115106477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60057553248 + 60057553249.

It is an arithmetic number, because the mean of its divisors is an integer number (60057553249).

Almost surely, 2120115106497 is an apocalyptic number.

It is an amenable number.

120115106497 is a deficient number, since it is larger than the sum of its proper divisors (1).

120115106497 is an equidigital number, since it uses as much as digits as its factorization.

120115106497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 37.

The spelling of 120115106497 in words is "one hundred twenty billion, one hundred fifteen million, one hundred six thousand, four hundred ninety-seven".