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12012104003 is a prime number
BaseRepresentation
bin10110010111111101…
…00010100101000011
31011000010220002220212
423023332202211003
5144100044312003
65303541024335
7603446125244
oct131376424503
934003802825
1012012104003
115104579589
1223b29b50ab
131195811c63
1481d48cccb
154a4861dd8
hex2cbfa2943

12012104003 has 2 divisors, whose sum is σ = 12012104004. Its totient is φ = 12012104002.

The previous prime is 12012103897. The next prime is 12012104011. The reversal of 12012104003 is 30040121021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12012104003 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (12012104053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006052001 + 6006052002.

It is an arithmetic number, because the mean of its divisors is an integer number (6006052002).

Almost surely, 212012104003 is an apocalyptic number.

12012104003 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012104003 is an equidigital number, since it uses as much as digits as its factorization.

12012104003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 12012104003 its reverse (30040121021), we get a palindrome (42052225024).

The spelling of 12012104003 in words is "twelve billion, twelve million, one hundred four thousand, three".