Base | Representation |
---|---|
bin | 1010111011001100100110… |
… | …1110101100100110001011 |
3 | 1120112100100210212100020211 |
4 | 2232303021232230212023 |
5 | 3033301301413140243 |
6 | 41314142154101551 |
7 | 2346563234003332 |
oct | 256631156544613 |
9 | 46470323770224 |
10 | 12012113021323 |
11 | 3911343711028 |
12 | 142004041a8b7 |
13 | 6919780a6a1c |
14 | 2d756461ad19 |
15 | 15c6e1568d9d |
hex | aecc9bac98b |
12012113021323 has 8 divisors (see below), whose sum is σ = 12337038738992. Its totient is φ = 11687201725536.
The previous prime is 12012113021309. The next prime is 12012113021347. The reversal of 12012113021323 is 32312031121021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12012113021323 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12012113021294 and 12012113021303.
It is not an unprimeable number, because it can be changed into a prime (12012113001323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1906440 + ... + 5259157.
It is an arithmetic number, because the mean of its divisors is an integer number (1542129842374).
Almost surely, 212012113021323 is an apocalyptic number.
12012113021323 is a deficient number, since it is larger than the sum of its proper divisors (324925717669).
12012113021323 is an equidigital number, since it uses as much as digits as its factorization.
12012113021323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7210941.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 12012113021323 its reverse (32312031121021), we get a palindrome (44324144142344).
The spelling of 12012113021323 in words is "twelve trillion, twelve billion, one hundred thirteen million, twenty-one thousand, three hundred twenty-three".
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