Search a number
-
+
12012122099947 is a prime number
BaseRepresentation
bin1010111011001100101001…
…0001010101000011101011
31120112100101102221120210011
42232303022101111003223
53033301311224144242
641314143120432351
72346563404114534
oct256631221250353
946470342846704
1012012122099947
113911348851a22
1214200434786b7
13691979c350a8
142d756590168b
1515c6e225dd17
hexaecca4550eb

12012122099947 has 2 divisors, whose sum is σ = 12012122099948. Its totient is φ = 12012122099946.

The previous prime is 12012122099941. The next prime is 12012122100053. The reversal of 12012122099947 is 74999022121021.

12012122099947 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (74999022121021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12012122099947 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12012122099947.

It is not a weakly prime, because it can be changed into another prime (12012122099941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006061049973 + 6006061049974.

It is an arithmetic number, because the mean of its divisors is an integer number (6006061049974).

Almost surely, 212012122099947 is an apocalyptic number.

12012122099947 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012122099947 is an equidigital number, since it uses as much as digits as its factorization.

12012122099947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 326592, while the sum is 49.

The spelling of 12012122099947 in words is "twelve trillion, twelve billion, one hundred twenty-two million, ninety-nine thousand, nine hundred forty-seven".