Base | Representation |
---|---|
bin | 1010111011001100101011… |
… | …0000101100101011110011 |
3 | 1120112100102000102100221121 |
4 | 2232303022300230223303 |
5 | 3033301320330320222 |
6 | 41314144013003111 |
7 | 2346563534034151 |
oct | 256631260545363 |
9 | 46470360370847 |
10 | 12012130323187 |
11 | 3911352459195 |
12 | 1420046183497 |
13 | 69197b854007 |
14 | 2d7566a423d1 |
15 | 15c6e2d355c7 |
hex | aeccac2caf3 |
12012130323187 has 2 divisors, whose sum is σ = 12012130323188. Its totient is φ = 12012130323186.
The previous prime is 12012130323181. The next prime is 12012130323223. The reversal of 12012130323187 is 78132303121021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12012130323187 is a prime.
It is a super-4 number, since 4×120121303231874 (a number of 53 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (12012130323181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006065161593 + 6006065161594.
It is an arithmetic number, because the mean of its divisors is an integer number (6006065161594).
Almost surely, 212012130323187 is an apocalyptic number.
12012130323187 is a deficient number, since it is larger than the sum of its proper divisors (1).
12012130323187 is an equidigital number, since it uses as much as digits as its factorization.
12012130323187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 34.
The spelling of 12012130323187 in words is "twelve trillion, twelve billion, one hundred thirty million, three hundred twenty-three thousand, one hundred eighty-seven".
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