Base | Representation |
---|---|
bin | 10110010111111101… |
… | …01010010000001011 |
3 | 1011000010221201001000 |
4 | 23023332222100023 |
5 | 144100101313220 |
6 | 5303541430043 |
7 | 603446316006 |
oct | 131376522013 |
9 | 34003851030 |
10 | 12012135435 |
11 | 51045a0163 |
12 | 23b2a0b323 |
13 | 1195823361 |
14 | 81d49a53d |
15 | 4a486b390 |
hex | 2cbfaa40b |
12012135435 has 32 divisors (see below), whose sum is σ = 21416532480. Its totient is φ = 6387984864.
The previous prime is 12012135427. The next prime is 12012135467. The reversal of 12012135435 is 53453121021.
12012135435 is a `hidden beast` number, since 1 + 201 + 21 + 3 + 5 + 435 = 666.
It is not a de Polignac number, because 12012135435 - 23 = 12012135427 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 12012135399 and 12012135408.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 81367 + ... + 175056.
It is an arithmetic number, because the mean of its divisors is an integer number (669266640).
Almost surely, 212012135435 is an apocalyptic number.
12012135435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12012135435 is a deficient number, since it is larger than the sum of its proper divisors (9404397045).
12012135435 is a wasteful number, since it uses less digits than its factorization.
12012135435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 256784 (or 256778 counting only the distinct ones).
The product of its (nonzero) digits is 3600, while the sum is 27.
Adding to 12012135435 its reverse (53453121021), we get a palindrome (65465256456).
The spelling of 12012135435 in words is "twelve billion, twelve million, one hundred thirty-five thousand, four hundred thirty-five".
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