Base | Representation |
---|---|
bin | 10001011110101110010… |
… | …010101000010010111001 |
3 | 11020211120002100021020101 |
4 | 101132232102220102321 |
5 | 124140044304313214 |
6 | 2315455521155401 |
7 | 152533231326142 |
oct | 21365622502271 |
9 | 4224502307211 |
10 | 1201219994809 |
11 | 42348640a26a |
12 | 17497a18bb61 |
13 | 89375290123 |
14 | 421d4580ac9 |
15 | 213a6d75774 |
hex | 117ae4a84b9 |
1201219994809 has 2 divisors, whose sum is σ = 1201219994810. Its totient is φ = 1201219994808.
The previous prime is 1201219994803. The next prime is 1201219994851. The reversal of 1201219994809 is 9084999121021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1198860755625 + 2359239184 = 1094925^2 + 48572^2 .
It is a cyclic number.
It is not a de Polignac number, because 1201219994809 - 221 = 1201217897657 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1201219994809.
It is not a weakly prime, because it can be changed into another prime (1201219994803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600609997404 + 600609997405.
It is an arithmetic number, because the mean of its divisors is an integer number (600609997405).
Almost surely, 21201219994809 is an apocalyptic number.
It is an amenable number.
1201219994809 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201219994809 is an equidigital number, since it uses as much as digits as its factorization.
1201219994809 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 839808, while the sum is 55.
The spelling of 1201219994809 in words is "one trillion, two hundred one billion, two hundred nineteen million, nine hundred ninety-four thousand, eight hundred nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •