Base | Representation |
---|---|
bin | 11011010100000000010101… |
… | …110111001011010000111010 |
3 | 120202022112220120002221100101 |
4 | 123110000111313023100322 |
5 | 111221034340100320442 |
6 | 1103251142432030014 |
7 | 34205346304121035 |
oct | 3324002567132072 |
9 | 522275816087311 |
10 | 120122012120122 |
11 | 353025062a3a21 |
12 | 1158054a99230a |
13 | 52045c3442c5c |
14 | 2193d1770801c |
15 | dd49b10b4cb7 |
hex | 6d4015dcb43a |
120122012120122 has 4 divisors (see below), whose sum is σ = 180183018180186. Its totient is φ = 60061006060060.
The previous prime is 120122012120053. The next prime is 120122012120129. The reversal of 120122012120122 is 221021210221021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 103564591935561 + 16557420184561 = 10176669^2 + 4069081^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 120122012120122.
It is not an unprimeable number, because it can be changed into a prime (120122012120129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30030503030029 + ... + 30030503030032.
Almost surely, 2120122012120122 is an apocalyptic number.
120122012120122 is a deficient number, since it is larger than the sum of its proper divisors (60061006060064).
120122012120122 is an equidigital number, since it uses as much as digits as its factorization.
120122012120122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60061006060063.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 120122012120122 its reverse (221021210221021), we get a palindrome (341143222341143).
The spelling of 120122012120122 in words is "one hundred twenty trillion, one hundred twenty-two billion, twelve million, one hundred twenty thousand, one hundred twenty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •