Base | Representation |
---|---|
bin | 110111111011111100… |
… | …0111000010100110001 |
3 | 102111001120121122221012 |
4 | 1233313320320110301 |
5 | 3432002442000423 |
6 | 131103404440305 |
7 | 11451521440214 |
oct | 1576770702461 |
9 | 374046548835 |
10 | 120123000113 |
11 | 46a42335a06 |
12 | 1b344b49095 |
13 | b4348219bc |
14 | 5b5780377b |
15 | 31d0ba0078 |
hex | 1bf7e38531 |
120123000113 has 8 divisors (see below), whose sum is σ = 120744531840. Its totient is φ = 119502779760.
The previous prime is 120123000079. The next prime is 120123000119. The reversal of 120123000113 is 311000321021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 120123000113 - 210 = 120122999089 is a prime.
It is a super-2 number, since 2×1201230001132 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120123000119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 143903 + ... + 510836.
It is an arithmetic number, because the mean of its divisors is an integer number (15093066480).
Almost surely, 2120123000113 is an apocalyptic number.
It is an amenable number.
120123000113 is a deficient number, since it is larger than the sum of its proper divisors (621531727).
120123000113 is an equidigital number, since it uses as much as digits as its factorization.
120123000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 655687.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 120123000113 its reverse (311000321021), we get a palindrome (431123321134).
The spelling of 120123000113 in words is "one hundred twenty billion, one hundred twenty-three million, one hundred thirteen", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •