Search a number
-
+
120123000113 = 271677654739
BaseRepresentation
bin110111111011111100…
…0111000010100110001
3102111001120121122221012
41233313320320110301
53432002442000423
6131103404440305
711451521440214
oct1576770702461
9374046548835
10120123000113
1146a42335a06
121b344b49095
13b4348219bc
145b5780377b
1531d0ba0078
hex1bf7e38531

120123000113 has 8 divisors (see below), whose sum is σ = 120744531840. Its totient is φ = 119502779760.

The previous prime is 120123000079. The next prime is 120123000119. The reversal of 120123000113 is 311000321021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120123000113 - 210 = 120122999089 is a prime.

It is a super-2 number, since 2×1201230001132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120123000119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 143903 + ... + 510836.

It is an arithmetic number, because the mean of its divisors is an integer number (15093066480).

Almost surely, 2120123000113 is an apocalyptic number.

It is an amenable number.

120123000113 is a deficient number, since it is larger than the sum of its proper divisors (621531727).

120123000113 is an equidigital number, since it uses as much as digits as its factorization.

120123000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 655687.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 120123000113 its reverse (311000321021), we get a palindrome (431123321134).

The spelling of 120123000113 in words is "one hundred twenty billion, one hundred twenty-three million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 271 677 183467 654739 177434269 443258303 120123000113