Base | Representation |
---|---|
bin | 110111111011111110… |
… | …1101000000010010001 |
3 | 102111001122221212101021 |
4 | 1233313331220002101 |
5 | 3432003301302423 |
6 | 131103451235441 |
7 | 11451535141066 |
oct | 1576775500221 |
9 | 374048855337 |
10 | 120124244113 |
11 | 46a43005605 |
12 | 1b345448b81 |
13 | b434b68cb3 |
14 | 5b57a48c6d |
15 | 31d0d4895d |
hex | 1bf7f68091 |
120124244113 has 4 divisors (see below), whose sum is σ = 120126066228. Its totient is φ = 120122422000.
The previous prime is 120124244099. The next prime is 120124244171. The reversal of 120124244113 is 311442421021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 62494000144 + 57630243969 = 249988^2 + 240063^2 .
It is a cyclic number.
It is not a de Polignac number, because 120124244113 - 25 = 120124244081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120124244183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808306 + ... + 945307.
It is an arithmetic number, because the mean of its divisors is an integer number (30031516557).
Almost surely, 2120124244113 is an apocalyptic number.
It is an amenable number.
120124244113 is a deficient number, since it is larger than the sum of its proper divisors (1822115).
120124244113 is an equidigital number, since it uses as much as digits as its factorization.
120124244113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1822114.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 120124244113 its reverse (311442421021), we get a palindrome (431566665134).
The spelling of 120124244113 in words is "one hundred twenty billion, one hundred twenty-four million, two hundred forty-four thousand, one hundred thirteen".
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