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120124244113 = 685011753613
BaseRepresentation
bin110111111011111110…
…1101000000010010001
3102111001122221212101021
41233313331220002101
53432003301302423
6131103451235441
711451535141066
oct1576775500221
9374048855337
10120124244113
1146a43005605
121b345448b81
13b434b68cb3
145b57a48c6d
1531d0d4895d
hex1bf7f68091

120124244113 has 4 divisors (see below), whose sum is σ = 120126066228. Its totient is φ = 120122422000.

The previous prime is 120124244099. The next prime is 120124244171. The reversal of 120124244113 is 311442421021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 62494000144 + 57630243969 = 249988^2 + 240063^2 .

It is a cyclic number.

It is not a de Polignac number, because 120124244113 - 25 = 120124244081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120124244183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 808306 + ... + 945307.

It is an arithmetic number, because the mean of its divisors is an integer number (30031516557).

Almost surely, 2120124244113 is an apocalyptic number.

It is an amenable number.

120124244113 is a deficient number, since it is larger than the sum of its proper divisors (1822115).

120124244113 is an equidigital number, since it uses as much as digits as its factorization.

120124244113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1822114.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 120124244113 its reverse (311442421021), we get a palindrome (431566665134).

The spelling of 120124244113 in words is "one hundred twenty billion, one hundred twenty-four million, two hundred forty-four thousand, one hundred thirteen".

Divisors: 1 68501 1753613 120124244113