Base | Representation |
---|---|
bin | 1010111011001110001101… |
… | …1010110101001100110111 |
3 | 1120112101110211212102002001 |
4 | 2232303203122311030313 |
5 | 3033303142232140203 |
6 | 41314253032000131 |
7 | 2346610016310130 |
oct | 256634332651467 |
9 | 46471424772061 |
10 | 12012544021303 |
11 | 3911544a2a761 |
12 | 1420140830047 |
13 | 691a164804b7 |
14 | 2d75a5970c87 |
15 | 15c71930291d |
hex | aece36b5337 |
12012544021303 has 32 divisors (see below), whose sum is σ = 14386270464000. Its totient is φ = 9812520506880.
The previous prime is 12012544021297. The next prime is 12012544021307. The reversal of 12012544021303 is 30312044521021.
It is not a de Polignac number, because 12012544021303 - 233 = 12003954086711 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12012544021307) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 52149663 + ... + 52379503.
It is an arithmetic number, because the mean of its divisors is an integer number (449570952000).
Almost surely, 212012544021303 is an apocalyptic number.
12012544021303 is a deficient number, since it is larger than the sum of its proper divisors (2373726442697).
12012544021303 is a wasteful number, since it uses less digits than its factorization.
12012544021303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 233215.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 12012544021303 its reverse (30312044521021), we get a palindrome (42324588542324).
The spelling of 12012544021303 in words is "twelve trillion, twelve billion, five hundred forty-four million, twenty-one thousand, three hundred three".
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