120130011030331 has 4 divisors (see below), whose sum is σ = 120557519966664. Its totient is φ = 119702502094000.

The previous prime is 120130011030319. The next prime is 120130011030401. The reversal of 120130011030331 is 133030110031021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120130011030331 - 2⁵ = 120130011030299 is a prime.

It is a super-2 number, since 2×120130011030331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120130011030299 and 120130011030308.

It is not an unprimeable number, because it can be changed into a prime (120130011730331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213754467745 + ... + 213754468306.

It is an arithmetic number, because the mean of its divisors is an integer number (30139379991666).

Almost surely, 2^{120130011030331} is an apocalyptic number.

120130011030331 is a deficient number, since it is larger than the sum of its proper divisors (427508936333).

120130011030331 is an equidigital number, since it uses as much as digits as its factorization.

120130011030331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 427508936332.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 120130011030331 its reverse (133030110031021), we get a palindrome (253160121061352).

The spelling of 120130011030331 in words is "one hundred twenty trillion, one hundred thirty billion, eleven million, thirty thousand, three hundred thirty-one".