Base | Representation |
---|---|
bin | 1010111011001111111100… |
… | …1101111011001111110001 |
3 | 1120112102200100102220201001 |
4 | 2232303333031323033301 |
5 | 3033310121130301431 |
6 | 41314411212042001 |
7 | 2346624411414364 |
oct | 256637715731761 |
9 | 46472610386631 |
10 | 12013010400241 |
11 | 39117642130a4 |
12 | 1420250a63301 |
13 | 691a8bc93376 |
14 | 2d760b8940db |
15 | 15c745228e61 |
hex | aecff37b3f1 |
12013010400241 has 2 divisors, whose sum is σ = 12013010400242. Its totient is φ = 12013010400240.
The previous prime is 12013010400211. The next prime is 12013010400257. The reversal of 12013010400241 is 14200401031021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9736771344400 + 2276239055841 = 3120380^2 + 1508721^2 .
It is a cyclic number.
It is not a de Polignac number, because 12013010400241 - 27 = 12013010400113 is a prime.
It is not a weakly prime, because it can be changed into another prime (12013010400211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006505200120 + 6006505200121.
It is an arithmetic number, because the mean of its divisors is an integer number (6006505200121).
Almost surely, 212013010400241 is an apocalyptic number.
It is an amenable number.
12013010400241 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013010400241 is an equidigital number, since it uses as much as digits as its factorization.
12013010400241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 12013010400241 its reverse (14200401031021), we get a palindrome (26213411431262).
The spelling of 12013010400241 in words is "twelve trillion, thirteen billion, ten million, four hundred thousand, two hundred forty-one".
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