Base | Representation |
---|---|
bin | 1010111011001111111111… |
… | …0011000000001111001100 |
3 | 1120112102201000201201201120 |
4 | 2232303333303000033030 |
5 | 3033310131122320022 |
6 | 41314412200240540 |
7 | 2346624560136042 |
oct | 256637763001714 |
9 | 46472630651646 |
10 | 12013020120012 |
11 | 391176975176a |
12 | 1420254170150 |
13 | 691a90cb7502 |
14 | 2d760cca4392 |
15 | 15c745ee8d5c |
hex | aecffcc03cc |
12013020120012 has 24 divisors (see below), whose sum is σ = 28714048092912. Its totient is φ = 3906673209600.
The previous prime is 12013020119981. The next prime is 12013020120029. The reversal of 12013020120012 is 21002102031021.
It is a junction number, because it is equal to n+sod(n) for n = 12013020119973 and 12013020120000.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12208353289 + ... + 12208354272.
It is an arithmetic number, because the mean of its divisors is an integer number (1196418670538).
Almost surely, 212013020120012 is an apocalyptic number.
12013020120012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12013020120012 is an abundant number, since it is smaller than the sum of its proper divisors (16701027972900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12013020120012 is a wasteful number, since it uses less digits than its factorization.
12013020120012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24416707609 (or 24416707607 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 12013020120012 its reverse (21002102031021), we get a palindrome (33015122151033).
The spelling of 12013020120012 in words is "twelve trillion, thirteen billion, twenty million, one hundred twenty thousand, twelve".
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