12013022012131 has 8 divisors (see below), whose sum is σ = 14172044401664. Its totient is φ = 9964718719560.

The previous prime is 12013022012111. The next prime is 12013022012137. The reversal of 12013022012131 is 13121022031021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12013022012131 - 2⁵ = 12013022012099 is a prime.

It is a super-2 number, since 2×12013022012131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12013022012099 and 12013022012108.

It is not an unprimeable number, because it can be changed into a prime (12013022012137) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27679774005 + ... + 27679774438.

It is an arithmetic number, because the mean of its divisors is an integer number (1771505550208).

Almost surely, 2^{12013022012131} is an apocalyptic number.

12013022012131 is a deficient number, since it is larger than the sum of its proper divisors (2159022389533).

12013022012131 is an equidigital number, since it uses as much as digits as its factorization.

12013022012131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55359548481.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 12013022012131 its reverse (13121022031021), we get a palindrome (25134044043152).

The spelling of 12013022012131 in words is "twelve trillion, thirteen billion, twenty-two million, twelve thousand, one hundred thirty-one".