12013030220033 has 4 divisors (see below), whose sum is σ = 12013048728240. Its totient is φ = 12013011711828.

The previous prime is 12013030220029. The next prime is 12013030220069. The reversal of 12013030220033 is 33002203031021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12013030220033 - 2² = 12013030220029 is a prime.

It is a super-2 number, since 2×12013030220033² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12013030219987 and 12013030220014.

It is not an unprimeable number, because it can be changed into a prime (12013030222033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8243735 + ... + 9590892.

It is an arithmetic number, because the mean of its divisors is an integer number (3003262182060).

Almost surely, 2^{12013030220033} is an apocalyptic number.

It is an amenable number.

12013030220033 is a deficient number, since it is larger than the sum of its proper divisors (18508207).

12013030220033 is an equidigital number, since it uses as much as digits as its factorization.

12013030220033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18508206.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 12013030220033 its reverse (33002203031021), we get a palindrome (45015233251054).

The spelling of 12013030220033 in words is "twelve trillion, thirteen billion, thirty million, two hundred twenty thousand, thirty-three".