Base | Representation |
---|---|
bin | 11011010100001000000100… |
… | …000010011111111100101100 |
3 | 120202100100022100220221212121 |
4 | 123110020010002133330230 |
5 | 111221203330034030012 |
6 | 1103255033243042324 |
7 | 34206061616533060 |
oct | 3324100402377454 |
9 | 522310270827777 |
10 | 120130303033132 |
11 | 35305a802a9647 |
12 | 115820835103a4 |
13 | 5205315021a42 |
14 | 21944a289baa0 |
15 | dd4ce8dc6a07 |
hex | 6d420409ff2c |
120130303033132 has 48 divisors (see below), whose sum is σ = 246123974214720. Its totient is φ = 50228013772800.
The previous prime is 120130303033031. The next prime is 120130303033157. The reversal of 120130303033132 is 231330303031021.
It is a junction number, because it is equal to n+sod(n) for n = 120130303033097 and 120130303033106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 88434844 + ... + 89782972.
It is an arithmetic number, because the mean of its divisors is an integer number (5127582796140).
Almost surely, 2120130303033132 is an apocalyptic number.
It is an amenable number.
120130303033132 is an abundant number, since it is smaller than the sum of its proper divisors (125993671181588).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120130303033132 is a wasteful number, since it uses less digits than its factorization.
120130303033132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1425802 (or 1425800 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 120130303033132 its reverse (231330303031021), we get a palindrome (351460606064153).
The spelling of 120130303033132 in words is "one hundred twenty trillion, one hundred thirty billion, three hundred three million, thirty-three thousand, one hundred thirty-two".
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