Base | Representation |
---|---|
bin | 1010111011010000010010… |
… | …0111111101001011111101 |
3 | 1120112102220200010110010020 |
4 | 2232310010213331023331 |
5 | 3033310312341010023 |
6 | 41314424212202353 |
7 | 2346626562424353 |
oct | 256640447751375 |
9 | 46472820113106 |
10 | 12013101110013 |
11 | 3911800439753 |
12 | 14202773093b9 |
13 | 691aa4a033a3 |
14 | 2d76199477d3 |
15 | 15c74d195de3 |
hex | aed049fd2fd |
12013101110013 has 16 divisors (see below), whose sum is σ = 16063702898880. Its totient is φ = 7985631494016.
The previous prime is 12013101110009. The next prime is 12013101110029. The reversal of 12013101110013 is 31001110131021.
It is not a de Polignac number, because 12013101110013 - 22 = 12013101110009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12013101109974 and 12013101110001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12013101110033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1402206 + ... + 5098272.
It is an arithmetic number, because the mean of its divisors is an integer number (1003981431180).
Almost surely, 212013101110013 is an apocalyptic number.
It is an amenable number.
12013101110013 is a deficient number, since it is larger than the sum of its proper divisors (4050601788867).
12013101110013 is a wasteful number, since it uses less digits than its factorization.
12013101110013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3699196.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 12013101110013 its reverse (31001110131021), we get a palindrome (43014211241034).
The spelling of 12013101110013 in words is "twelve trillion, thirteen billion, one hundred one million, one hundred ten thousand, thirteen".
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