1201310112169 has 2 divisors, whose sum is σ = 1201310112170. Its totient is φ = 1201310112168.

The previous prime is 1201310112161. The next prime is 1201310112221. The reversal of 1201310112169 is 9612110131021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 697759502400 + 503550609769 = 835320^2 + 709613^2 .

It is an emirp because it is prime and its reverse (9612110131021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1201310112169 - 2³ = 1201310112161 is a prime.

It is a super-2 number, since 2×1201310112169² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1201310112161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600655056084 + 600655056085.

It is an arithmetic number, because the mean of its divisors is an integer number (600655056085).

Almost surely, 2^{1201310112169} is an apocalyptic number.

It is an amenable number.

1201310112169 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201310112169 is an equidigital number, since it uses as much as digits as its factorization.

1201310112169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 28.

The spelling of 1201310112169 in words is "one trillion, two hundred one billion, three hundred ten million, one hundred twelve thousand, one hundred sixty-nine".