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12013102102201 = 49339243480859
BaseRepresentation
bin1010111011010000010010…
…1011101111011010111001
31120112102220201222212010221
42232310010223233122321
53033310313114232301
641314424245340041
72346626604026134
oct256640453573271
946472821885127
1012013102102201
113911800a57142
121420277707621
13691aa4c8cb95
142d7619b2521b
1515c74d2deda1
hexaed04aef6b9

12013102102201 has 4 divisors (see below), whose sum is σ = 12013345632400. Its totient is φ = 12012858572004.

The previous prime is 12013102102187. The next prime is 12013102102217. The reversal of 12013102102201 is 10220120131021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12013102102201 - 239 = 11463346288313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013102102241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121691091 + ... + 121789768.

It is an arithmetic number, because the mean of its divisors is an integer number (3003336408100).

Almost surely, 212013102102201 is an apocalyptic number.

It is an amenable number.

12013102102201 is a deficient number, since it is larger than the sum of its proper divisors (243530199).

12013102102201 is an equidigital number, since it uses as much as digits as its factorization.

12013102102201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 243530198.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12013102102201 its reverse (10220120131021), we get a palindrome (22233222233222).

The spelling of 12013102102201 in words is "twelve trillion, thirteen billion, one hundred two million, one hundred two thousand, two hundred one".

Divisors: 1 49339 243480859 12013102102201