Base | Representation |
---|---|
bin | 110111111100001011… |
… | …1100101111001101011 |
3 | 102111002010202200211110 |
4 | 1233320113211321223 |
5 | 3432012022113430 |
6 | 131104253201403 |
7 | 11451650041425 |
oct | 1577027457153 |
9 | 374063680743 |
10 | 120131051115 |
11 | 46a46934829 |
12 | 1b347790263 |
13 | b4363b03ca |
14 | 5b588db815 |
15 | 31d17407b0 |
hex | 1bf85e5e6b |
120131051115 has 16 divisors (see below), whose sum is σ = 193973076000. Its totient is φ = 63482095872.
The previous prime is 120131051083. The next prime is 120131051137. The reversal of 120131051115 is 511150131021.
It is not a de Polignac number, because 120131051115 - 25 = 120131051083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120131051091 and 120131051100.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 36735690 + ... + 36738959.
It is an arithmetic number, because the mean of its divisors is an integer number (12123317250).
Almost surely, 2120131051115 is an apocalyptic number.
120131051115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
120131051115 is a deficient number, since it is larger than the sum of its proper divisors (73842024885).
120131051115 is a wasteful number, since it uses less digits than its factorization.
120131051115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 73474766.
The product of its (nonzero) digits is 150, while the sum is 21.
Adding to 120131051115 its reverse (511150131021), we get a palindrome (631281182136).
The spelling of 120131051115 in words is "one hundred twenty billion, one hundred thirty-one million, fifty-one thousand, one hundred fifteen".
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