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120131211023099 is a prime number
BaseRepresentation
bin11011010100001000111010…
…001010001101001011111011
3120202100102122122110121221122
4123110020322022031023323
5111221212210010214344
61103255303320255455
734206123253400123
oct3324107212151373
9522312578417848
10120131211023099
11353063a6898981
121158229761158b
13520542b185103
14219454b2d7c83
15dd4d4d980aee
hex6d423a28d2fb

120131211023099 has 2 divisors, whose sum is σ = 120131211023100. Its totient is φ = 120131211023098.

The previous prime is 120131211023077. The next prime is 120131211023149. The reversal of 120131211023099 is 990320112131021.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120131211023099 is a prime.

It is not a weakly prime, because it can be changed into another prime (120131211023009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065605511549 + 60065605511550.

It is an arithmetic number, because the mean of its divisors is an integer number (60065605511550).

Almost surely, 2120131211023099 is an apocalyptic number.

120131211023099 is a deficient number, since it is larger than the sum of its proper divisors (1).

120131211023099 is an equidigital number, since it uses as much as digits as its factorization.

120131211023099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 35.

The spelling of 120131211023099 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred eleven million, twenty-three thousand, ninety-nine".