Base | Representation |
---|---|
bin | 11011010100001000111010… |
… | …001010001101001011111011 |
3 | 120202100102122122110121221122 |
4 | 123110020322022031023323 |
5 | 111221212210010214344 |
6 | 1103255303320255455 |
7 | 34206123253400123 |
oct | 3324107212151373 |
9 | 522312578417848 |
10 | 120131211023099 |
11 | 353063a6898981 |
12 | 1158229761158b |
13 | 520542b185103 |
14 | 219454b2d7c83 |
15 | dd4d4d980aee |
hex | 6d423a28d2fb |
120131211023099 has 2 divisors, whose sum is σ = 120131211023100. Its totient is φ = 120131211023098.
The previous prime is 120131211023077. The next prime is 120131211023149. The reversal of 120131211023099 is 990320112131021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120131211023099 is a prime.
It is not a weakly prime, because it can be changed into another prime (120131211023009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065605511549 + 60065605511550.
It is an arithmetic number, because the mean of its divisors is an integer number (60065605511550).
Almost surely, 2120131211023099 is an apocalyptic number.
120131211023099 is a deficient number, since it is larger than the sum of its proper divisors (1).
120131211023099 is an equidigital number, since it uses as much as digits as its factorization.
120131211023099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 35.
The spelling of 120131211023099 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred eleven million, twenty-three thousand, ninety-nine".
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