120131221101097 has 2 divisors, whose sum is σ = 120131221101098. Its totient is φ = 120131221101096.

The previous prime is 120131221101061. The next prime is 120131221101107. The reversal of 120131221101097 is 790101122131021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108082970519616 + 12048250581481 = 10396296^2 + 3471059^2 .

It is an emirp because it is prime and its reverse (790101122131021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120131221101097 - 2¹¹ = 120131221099049 is a prime.

It is not a weakly prime, because it can be changed into another prime (120131221108097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60065610550548 + 60065610550549.

It is an arithmetic number, because the mean of its divisors is an integer number (60065610550549).

Almost surely, 2^{120131221101097} is an apocalyptic number.

It is an amenable number.

120131221101097 is a deficient number, since it is larger than the sum of its proper divisors (1).

120131221101097 is an equidigital number, since it uses as much as digits as its factorization.

120131221101097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 31.

The spelling of 120131221101097 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred twenty-one million, one hundred one thousand, ninety-seven".