Base | Representation |
---|---|
bin | 11011010100001000111010… |
… | …110000101001101001001100 |
3 | 120202100102200100102122102010 |
4 | 123110020322300221221030 |
5 | 111221212220100214012 |
6 | 1103255304320301220 |
7 | 34206123435143133 |
oct | 3324107260515114 |
9 | 522312610378363 |
10 | 120131221101132 |
11 | 3530640155172a |
12 | 1158229aa71810 |
13 | 52054302a3347 |
14 | 219454c79c91a |
15 | dd4d4e7c1c3c |
hex | 6d423ac29a4c |
120131221101132 has 48 divisors (see below), whose sum is σ = 295696416565760. Its totient is φ = 37854239467968.
The previous prime is 120131221101107. The next prime is 120131221101149. The reversal of 120131221101132 is 231101122131021.
It is a junction number, because it is equal to n+sod(n) for n = 120131221101099 and 120131221101108.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 568891543 + ... + 569102670.
Almost surely, 2120131221101132 is an apocalyptic number.
120131221101132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
120131221101132 is an abundant number, since it is smaller than the sum of its proper divisors (175565195464628).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120131221101132 is a wasteful number, since it uses less digits than its factorization.
120131221101132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1137994702 (or 1137994700 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 120131221101132 its reverse (231101122131021), we get a palindrome (351232343232153).
The spelling of 120131221101132 in words is "one hundred twenty trillion, one hundred thirty-one billion, two hundred twenty-one million, one hundred one thousand, one hundred thirty-two".
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