1201314044219 has 2 divisors, whose sum is σ = 1201314044220. Its totient is φ = 1201314044218.

The previous prime is 1201314044159. The next prime is 1201314044243. The reversal of 1201314044219 is 9124404131021.

It is a strong prime.

It is an emirp because it is prime and its reverse (9124404131021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201314044219 is a prime.

It is a super-2 number, since 2×1201314044219² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1201310044219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600657022109 + 600657022110.

It is an arithmetic number, because the mean of its divisors is an integer number (600657022110).

Almost surely, 2^{1201314044219} is an apocalyptic number.

1201314044219 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201314044219 is an equidigital number, since it uses as much as digits as its factorization.

1201314044219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 32.

The spelling of 1201314044219 in words is "one trillion, two hundred one billion, three hundred fourteen million, forty-four thousand, two hundred nineteen".