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12013205200211 is a prime number
BaseRepresentation
bin1010111011010000101011…
…0101000001110101010011
31120112110011220222210000202
42232310022311001311103
53033311021012401321
641314442411205415
72346632265243335
oct256641265016523
946473156883022
1012013205200211
113911854174206
1214202a614686b
13691ac0449817
142d76296c1455
1515c7573a770b
hexaed0ad41d53

12013205200211 has 2 divisors, whose sum is σ = 12013205200212. Its totient is φ = 12013205200210.

The previous prime is 12013205200109. The next prime is 12013205200219. The reversal of 12013205200211 is 11200250231021.

12013205200211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12013205200211 - 218 = 12013204938067 is a prime.

It is a super-2 number, since 2×120132052002112 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12013205200219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006602600105 + 6006602600106.

It is an arithmetic number, because the mean of its divisors is an integer number (6006602600106).

Almost surely, 212013205200211 is an apocalyptic number.

12013205200211 is a deficient number, since it is larger than the sum of its proper divisors (1).

12013205200211 is an equidigital number, since it uses as much as digits as its factorization.

12013205200211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 12013205200211 its reverse (11200250231021), we get a palindrome (23213455431232).

The spelling of 12013205200211 in words is "twelve trillion, thirteen billion, two hundred five million, two hundred thousand, two hundred eleven".