Base | Representation |
---|---|
bin | 11011010100001001110101… |
… | …101101110011110100000100 |
3 | 120202100112020021121200120200 |
4 | 123110021311231303310010 |
5 | 111221221231303241400 |
6 | 1103255550412330500 |
7 | 34206160105352442 |
oct | 3324116555636404 |
9 | 522315207550520 |
10 | 120132210212100 |
11 | 35306869908409 |
12 | 11582516173a30 |
13 | 520555a19a0c8 |
14 | 2194603cb3b92 |
15 | dd4dab551b00 |
hex | 6d4275b73d04 |
120132210212100 has 432 divisors, whose sum is σ = 403926445802880. Its totient is φ = 29770532812800.
The previous prime is 120132210212099. The next prime is 120132210212101. The reversal of 120132210212100 is 1212012231021.
120132210212100 is a `hidden beast` number, since 1 + 20 + 1 + 322 + 10 + 212 + 100 = 666.
It is an interprime number because it is at equal distance from previous prime (120132210212099) and next prime (120132210212101).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (120132210212101) by changing a digit.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 5909972137 + ... + 5909992463.
It is an arithmetic number, because the mean of its divisors is an integer number (935014920840).
Almost surely, 2120132210212100 is an apocalyptic number.
120132210212100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 120132210212100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (201963222901440).
120132210212100 is an abundant number, since it is smaller than the sum of its proper divisors (283794235590780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120132210212100 is a wasteful number, since it uses less digits than its factorization.
120132210212100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26940 (or 26930 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 120132210212100 its reverse (1212012231021), we get a palindrome (121344222443121).
The spelling of 120132210212100 in words is "one hundred twenty trillion, one hundred thirty-two billion, two hundred ten million, two hundred twelve thousand, one hundred".
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