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12013300154243 = 46474925849007
BaseRepresentation
bin1010111011010001000001…
…1111001111111110000011
31120112110102112122221110202
42232310100133033332003
53033311214314413433
641314500042315415
72346634530321263
oct256642037177603
946473375587422
1012013300154243
1139118a2829613
121420311ab8b6b
13691b0701463b
142d763815b7a3
1515c7608b1ee8
hexaed107cff83

12013300154243 has 4 divisors (see below), whose sum is σ = 12013326468000. Its totient is φ = 12013273840488.

The previous prime is 12013300154213. The next prime is 12013300154281. The reversal of 12013300154243 is 34245100331021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12013300154243 - 210 = 12013300153219 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12013300154213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12459755 + ... + 13389252.

It is an arithmetic number, because the mean of its divisors is an integer number (3003331617000).

Almost surely, 212013300154243 is an apocalyptic number.

12013300154243 is a deficient number, since it is larger than the sum of its proper divisors (26313757).

12013300154243 is an equidigital number, since it uses as much as digits as its factorization.

12013300154243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26313756.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 12013300154243 its reverse (34245100331021), we get a palindrome (46258400485264).

The spelling of 12013300154243 in words is "twelve trillion, thirteen billion, three hundred million, one hundred fifty-four thousand, two hundred forty-three".

Divisors: 1 464749 25849007 12013300154243