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1201331201113 = 2235387135431
BaseRepresentation
bin10001011110110100111…
…010110110010001011001
311020211211211121010121101
4101132310322312101121
5124140311241413423
62315514532511401
7152536051503601
oct21366472662131
94224754533541
101201331201113
114235331651aa
121749ab47b561
1389392328584
144220524bc01
15213b19e07ad
hex117b4eb6459

1201331201113 has 4 divisors (see below), whose sum is σ = 1206718336768. Its totient is φ = 1195944065460.

The previous prime is 1201331201111. The next prime is 1201331201141. The reversal of 1201331201113 is 3111021331021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1201331201113 - 21 = 1201331201111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1201331201111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2693567493 + ... + 2693567938.

It is an arithmetic number, because the mean of its divisors is an integer number (301679584192).

Almost surely, 21201331201113 is an apocalyptic number.

It is an amenable number.

1201331201113 is a deficient number, since it is larger than the sum of its proper divisors (5387135655).

1201331201113 is an equidigital number, since it uses as much as digits as its factorization.

1201331201113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5387135654.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1201331201113 its reverse (3111021331021), we get a palindrome (4312352532134).

The spelling of 1201331201113 in words is "one trillion, two hundred one billion, three hundred thirty-one million, two hundred one thousand, one hundred thirteen".

Divisors: 1 223 5387135431 1201331201113