Search a number
-
+
120133121113 = 155977057807
BaseRepresentation
bin110111111100001111…
…1011111010001011001
3102111002021122212100001
41233320133133101121
53432013034333423
6131104405413001
711452003452415
oct1577037372131
9374067585301
10120133121113
1146a48018a75
121b34840a161
13b436956665
145b58cb9d45
1531d19edcad
hex1bf87df459

120133121113 has 4 divisors (see below), whose sum is σ = 120210180480. Its totient is φ = 120056061748.

The previous prime is 120133121057. The next prime is 120133121149. The reversal of 120133121113 is 311121331021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120133121113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120133121513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38527345 + ... + 38530462.

It is an arithmetic number, because the mean of its divisors is an integer number (30052545120).

Almost surely, 2120133121113 is an apocalyptic number.

It is an amenable number.

120133121113 is a deficient number, since it is larger than the sum of its proper divisors (77059367).

120133121113 is an equidigital number, since it uses as much as digits as its factorization.

120133121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77059366.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 120133121113 its reverse (311121331021), we get a palindrome (431254452134).

The spelling of 120133121113 in words is "one hundred twenty billion, one hundred thirty-three million, one hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 1559 77057807 120133121113