Base | Representation |
---|---|
bin | 10001011110110100111… |
… | …010111101111001011011 |
3 | 11020211211211122201110012 |
4 | 101132310322331321123 |
5 | 124140311243413342 |
6 | 2315514533312135 |
7 | 152536051663631 |
oct | 21366472757133 |
9 | 4224754581405 |
10 | 1201331232347 |
11 | 423533186714 |
12 | 1749ab49564b |
13 | 8939233985c |
14 | 42205259351 |
15 | 213b19e9b82 |
hex | 117b4ebde5b |
1201331232347 has 2 divisors, whose sum is σ = 1201331232348. Its totient is φ = 1201331232346.
The previous prime is 1201331232319. The next prime is 1201331232371. The reversal of 1201331232347 is 7432321331021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1201331232347 - 214 = 1201331215963 is a prime.
It is not a weakly prime, because it can be changed into another prime (1201331232397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600665616173 + 600665616174.
It is an arithmetic number, because the mean of its divisors is an integer number (600665616174).
Almost surely, 21201331232347 is an apocalyptic number.
1201331232347 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201331232347 is an equidigital number, since it uses as much as digits as its factorization.
1201331232347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 32.
Adding to 1201331232347 its reverse (7432321331021), we get a palindrome (8633652563368).
The spelling of 1201331232347 in words is "one trillion, two hundred one billion, three hundred thirty-one million, two hundred thirty-two thousand, three hundred forty-seven".
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