Base | Representation |
---|---|
bin | 1010111011010001000110… |
… | …1000001101010101111001 |
3 | 1120112110110212122122001212 |
4 | 2232310101220031111321 |
5 | 3033311234213424433 |
6 | 41314502004252505 |
7 | 2346635152016423 |
oct | 256642150152571 |
9 | 46473425578055 |
10 | 12013319279993 |
11 | 3911902602019 |
12 | 14203183a1135 |
13 | 691b0ac7cb55 |
14 | 2d763a8d9813 |
15 | 15c7623ddd48 |
hex | aed11a0d579 |
12013319279993 has 2 divisors, whose sum is σ = 12013319279994. Its totient is φ = 12013319279992.
The previous prime is 12013319279989. The next prime is 12013319280023. The reversal of 12013319279993 is 39997291331021.
12013319279993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8696648184064 + 3316671095929 = 2949008^2 + 1821173^2 .
It is a cyclic number.
It is not a de Polignac number, because 12013319279993 - 22 = 12013319279989 is a prime.
It is not a weakly prime, because it can be changed into another prime (12013319279953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006659639996 + 6006659639997.
It is an arithmetic number, because the mean of its divisors is an integer number (6006659639997).
Almost surely, 212013319279993 is an apocalyptic number.
It is an amenable number.
12013319279993 is a deficient number, since it is larger than the sum of its proper divisors (1).
12013319279993 is an equidigital number, since it uses as much as digits as its factorization.
12013319279993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4960116, while the sum is 59.
The spelling of 12013319279993 in words is "twelve trillion, thirteen billion, three hundred nineteen million, two hundred seventy-nine thousand, nine hundred ninety-three".
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