Search a number
-
+
120133223113 is a prime number
BaseRepresentation
bin110111111100001111…
…1111000001011001001
3102111002021212001020211
41233320133320023021
53432013101114423
6131104411521121
711452004355661
oct1577037701311
9374067761224
10120133223113
1146a48088672
121b3484591a1
13b436990c07
145b58d051a1
1531d1a1e10d
hex1bf87f82c9

120133223113 has 2 divisors, whose sum is σ = 120133223114. Its totient is φ = 120133223112.

The previous prime is 120133223087. The next prime is 120133223149. The reversal of 120133223113 is 311322331021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78976174729 + 41157048384 = 281027^2 + 202872^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120133223113 is a prime.

It is not a weakly prime, because it can be changed into another prime (120133223183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60066611556 + 60066611557.

It is an arithmetic number, because the mean of its divisors is an integer number (60066611557).

Almost surely, 2120133223113 is an apocalyptic number.

It is an amenable number.

120133223113 is a deficient number, since it is larger than the sum of its proper divisors (1).

120133223113 is an equidigital number, since it uses as much as digits as its factorization.

120133223113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 120133223113 its reverse (311322331021), we get a palindrome (431455554134).

The spelling of 120133223113 in words is "one hundred twenty billion, one hundred thirty-three million, two hundred twenty-three thousand, one hundred thirteen".