Base | Representation |
---|---|
bin | 1010111011010001000111… |
… | …0111101010100110101011 |
3 | 1120112110111011021111101121 |
4 | 2232310101313222212223 |
5 | 3033311241233111021 |
6 | 41314502231200111 |
7 | 2346635231324041 |
oct | 256642167524653 |
9 | 46473434244347 |
10 | 12013323332011 |
11 | 391190491a3a1 |
12 | 1420319816037 |
13 | 691b0ba6b2b1 |
14 | 2d763b272391 |
15 | 15c76293e741 |
hex | aed11dea9ab |
12013323332011 has 4 divisors (see below), whose sum is σ = 12645603507400. Its totient is φ = 11381043156624.
The previous prime is 12013323331991. The next prime is 12013323332051. The reversal of 12013323332011 is 11023332331021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12013323332011 - 213 = 12013323323819 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12013323332051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 316140087666 + ... + 316140087703.
It is an arithmetic number, because the mean of its divisors is an integer number (3161400876850).
Almost surely, 212013323332011 is an apocalyptic number.
12013323332011 is a deficient number, since it is larger than the sum of its proper divisors (632280175389).
12013323332011 is an equidigital number, since it uses as much as digits as its factorization.
12013323332011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 632280175388.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 12013323332011 its reverse (11023332331021), we get a palindrome (23036655663032).
The spelling of 12013323332011 in words is "twelve trillion, thirteen billion, three hundred twenty-three million, three hundred thirty-two thousand, eleven".
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