1201340241003 has 32 divisors (see below), whose sum is σ = 1927348784640. Its totient is φ = 650218993920.

The previous prime is 1201340241001. The next prime is 1201340241019. The reversal of 1201340241003 is 3001420431021.

It is not a de Polignac number, because 1201340241003 - 2¹ = 1201340241001 is a prime.

It is a super-2 number, since 2×1201340241003² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is not an unprimeable number, because it can be changed into a prime (1201340241001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1703551 + ... + 2303207.

It is an arithmetic number, because the mean of its divisors is an integer number (60229649520).

Almost surely, 2^{1201340241003} is an apocalyptic number.

1201340241003 is a deficient number, since it is larger than the sum of its proper divisors (726008543637).

1201340241003 is a wasteful number, since it uses less digits than its factorization.

1201340241003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 604707.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1201340241003 its reverse (3001420431021), we get a palindrome (4202760672024).

The spelling of 1201340241003 in words is "one trillion, two hundred one billion, three hundred forty million, two hundred forty-one thousand, three".