1201360837297 has 2 divisors, whose sum is σ = 1201360837298. Its totient is φ = 1201360837296.

The previous prime is 1201360837279. The next prime is 1201360837363. The reversal of 1201360837297 is 7927380631021.

Together with previous prime (1201360837279) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1163462092321 + 37898744976 = 1078639^2 + 194676^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201360837297 - 2²⁷ = 1201226619569 is a prime.

It is a super-2 number, since 2×1201360837297² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1201360837297.

It is not a weakly prime, because it can be changed into another prime (1201360837207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600680418648 + 600680418649.

It is an arithmetic number, because the mean of its divisors is an integer number (600680418649).

Almost surely, 2^{1201360837297} is an apocalyptic number.

It is an amenable number.

1201360837297 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201360837297 is an equidigital number, since it uses as much as digits as its factorization.

1201360837297 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 762048, while the sum is 49.

The spelling of 1201360837297 in words is "one trillion, two hundred one billion, three hundred sixty million, eight hundred thirty-seven thousand, two hundred ninety-seven".