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120138945 = 3523833361
BaseRepresentation
bin1110010100100…
…10110011000001
322101001200122120
413022102303001
5221223421240
615530554453
72656110213
oct712226301
9271050576
10120138945
11618a7193
1234298a29
131bb75244
1411d545b3
15a831ad0
hex7292cc1

120138945 has 16 divisors (see below), whose sum is σ = 192360192. Its totient is φ = 64028160.

The previous prime is 120138943. The next prime is 120139007. The reversal of 120138945 is 549831021.

It is not a de Polignac number, because 120138945 - 21 = 120138943 is a prime.

It is a super-2 number, since 2×1201389452 = 28866732211426050, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (120138943) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34065 + ... + 37425.

It is an arithmetic number, because the mean of its divisors is an integer number (12022512).

Almost surely, 2120138945 is an apocalyptic number.

120138945 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

120138945 is a deficient number, since it is larger than the sum of its proper divisors (72221247).

120138945 is a wasteful number, since it uses less digits than its factorization.

120138945 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5752.

The product of its (nonzero) digits is 8640, while the sum is 33.

The square root of 120138945 is about 10960.7912579339. The cubic root of 120138945 is about 493.4327124584.

Adding to 120138945 its reverse (549831021), we get a palindrome (669969966).

The spelling of 120138945 in words is "one hundred twenty million, one hundred thirty-eight thousand, nine hundred forty-five".

Divisors: 1 3 5 15 2383 3361 7149 10083 11915 16805 35745 50415 8009263 24027789 40046315 120138945