Base | Representation |
---|---|
bin | 1010111011010011110101… |
… | …1000101001111010001001 |
3 | 1120112112101001000210200012 |
4 | 2232310331120221322021 |
5 | 3033314240132301301 |
6 | 41315102511121305 |
7 | 2346662304646526 |
oct | 256647530517211 |
9 | 46475331023605 |
10 | 12014053400201 |
11 | 3912149a36436 |
12 | 14204a2213235 |
13 | 691bc70a76c8 |
14 | 2d76aa1d614d |
15 | 15c7a6aa0ebb |
hex | aed3d629e89 |
12014053400201 has 16 divisors (see below), whose sum is σ = 12253575383040. Its totient is φ = 11776805773200.
The previous prime is 12014053400189. The next prime is 12014053400213. The reversal of 12014053400201 is 10200435041021.
It is an interprime number because it is at equal distance from previous prime (12014053400189) and next prime (12014053400213).
It is a de Polignac number, because none of the positive numbers 2k-12014053400201 is a prime.
It is a super-3 number, since 3×120140534002013 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12014053400281) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21035330 + ... + 21598916.
It is an arithmetic number, because the mean of its divisors is an integer number (765848461440).
Almost surely, 212014053400201 is an apocalyptic number.
It is an amenable number.
12014053400201 is a deficient number, since it is larger than the sum of its proper divisors (239521982839).
12014053400201 is a wasteful number, since it uses less digits than its factorization.
12014053400201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 565604.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 12014053400201 its reverse (10200435041021), we get a palindrome (22214488441222).
The spelling of 12014053400201 in words is "twelve trillion, fourteen billion, fifty-three million, four hundred thousand, two hundred one".
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