12014134125442 has 8 divisors (see below), whose sum is σ = 18026887913100. Its totient is φ = 6005171487744.

The previous prime is 12014134125341. The next prime is 12014134125589. The reversal of 12014134125442 is 24452143141021.

It can be written as a sum of positive squares in 2 ways, for example, as 11941164448801 + 72969676641 = 3455599^2 + 270129^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×12014134125442² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12014134125398 and 12014134125407.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 947779567 + ... + 947792242.

Almost surely, 2^{12014134125442} is an apocalyptic number.

12014134125442 is a deficient number, since it is larger than the sum of its proper divisors (6012753787658).

12014134125442 is a wasteful number, since it uses less digits than its factorization.

12014134125442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1895574980.

The product of its (nonzero) digits is 30720, while the sum is 34.

Adding to 12014134125442 its reverse (24452143141021), we get a palindrome (36466277266463).

The spelling of 12014134125442 in words is "twelve trillion, fourteen billion, one hundred thirty-four million, one hundred twenty-five thousand, four hundred forty-two".