Base | Representation |
---|---|
bin | 1010111011010100011010… |
… | …1110001010001000010011 |
3 | 1120112112202221202112022101 |
4 | 2232311012232022020103 |
5 | 3033320100232012042 |
6 | 41315130224221231 |
7 | 2346666216210451 |
oct | 256650656121023 |
9 | 46475687675271 |
10 | 12014210032147 |
11 | 391221a398324 |
12 | 142052676a817 |
13 | 691c2068912b |
14 | 2d76c2d299d1 |
15 | 15c7b56e06b7 |
hex | aed46b8a213 |
12014210032147 has 2 divisors, whose sum is σ = 12014210032148. Its totient is φ = 12014210032146.
The previous prime is 12014210032127. The next prime is 12014210032157. The reversal of 12014210032147 is 74123001241021.
It is a strong prime.
It is an emirp because it is prime and its reverse (74123001241021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12014210032147 - 211 = 12014210030099 is a prime.
It is not a weakly prime, because it can be changed into another prime (12014210032127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007105016073 + 6007105016074.
It is an arithmetic number, because the mean of its divisors is an integer number (6007105016074).
Almost surely, 212014210032147 is an apocalyptic number.
12014210032147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014210032147 is an equidigital number, since it uses as much as digits as its factorization.
12014210032147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 12014210032147 its reverse (74123001241021), we get a palindrome (86137211273168).
The spelling of 12014210032147 in words is "twelve trillion, fourteen billion, two hundred ten million, thirty-two thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •