Base | Representation |
---|---|
bin | 11011010100010011000011… |
… | …111111000110111001000011 |
3 | 120202101110210110000212222000 |
4 | 123110103003333012321003 |
5 | 111221402022001213011 |
6 | 1103304305214115043 |
7 | 34206660365301042 |
oct | 3324230377067103 |
9 | 522343713025860 |
10 | 120142113304131 |
11 | 3530aa90952a96 |
12 | 1158441a7aba83 |
13 | 5206477a87289 |
14 | 2194ca320c559 |
15 | dd528ab6b356 |
hex | 6d44c3fc6e43 |
120142113304131 has 16 divisors (see below), whose sum is σ = 178172378419200. Its totient is φ = 80011914116904.
The previous prime is 120142113304049. The next prime is 120142113304133. The reversal of 120142113304131 is 131403311241021.
120142113304131 is a `hidden beast` number, since 1 + 2 + 0 + 1 + 4 + 211 + 3 + 30 + 413 + 1 = 666.
It is not a de Polignac number, because 120142113304131 - 221 = 120142111206979 is a prime.
It is a super-2 number, since 2×1201421133041312 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 120142113304095 and 120142113304104.
It is not an unprimeable number, because it can be changed into a prime (120142113304133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2300753571 + ... + 2300805788.
It is an arithmetic number, because the mean of its divisors is an integer number (11135773651200).
Almost surely, 2120142113304131 is an apocalyptic number.
120142113304131 is a deficient number, since it is larger than the sum of its proper divisors (58030265115069).
120142113304131 is an equidigital number, since it uses as much as digits as its factorization.
120142113304131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4601560335 (or 4601560329 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 120142113304131 its reverse (131403311241021), we get a palindrome (251545424545152).
The spelling of 120142113304131 in words is "one hundred twenty trillion, one hundred forty-two billion, one hundred thirteen million, three hundred four thousand, one hundred thirty-one".
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