1201423340121 has 8 divisors (see below), whose sum is σ = 1601951547840. Its totient is φ = 800922012912.

The previous prime is 1201423340113. The next prime is 1201423340129. The reversal of 1201423340121 is 1210433241021.

It is an interprime number because it is at equal distance from previous prime (1201423340113) and next prime (1201423340129).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1201423340121 - 2³ = 1201423340113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201423340091 and 1201423340100.

It is not an unprimeable number, because it can be changed into a prime (1201423340129) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6615606 + ... + 6794783.

It is an arithmetic number, because the mean of its divisors is an integer number (200243943480).

Almost surely, 2^{1201423340121} is an apocalyptic number.

It is an amenable number.

1201423340121 is a deficient number, since it is larger than the sum of its proper divisors (400528207719).

1201423340121 is a wasteful number, since it uses less digits than its factorization.

1201423340121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13440255.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1201423340121 its reverse (1210433241021), we get a palindrome (2411856581142).

The spelling of 1201423340121 in words is "one trillion, two hundred one billion, four hundred twenty-three million, three hundred forty thousand, one hundred twenty-one".