120142420113 has 4 divisors (see below), whose sum is σ = 160189893488. Its totient is φ = 80094946740.

The previous prime is 120142420103. The next prime is 120142420157. The reversal of 120142420113 is 311024241021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 120142420113 - 2²⁹ = 119605549201 is a prime.

It is a super-2 number, since 2×120142420113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 120142420113.

It is not an unprimeable number, because it can be changed into a prime (120142420103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20023736683 + ... + 20023736688.

It is an arithmetic number, because the mean of its divisors is an integer number (40047473372).

Almost surely, 2^120142420113 is an apocalyptic number.

It is an amenable number.

120142420113 is a deficient number, since it is larger than the sum of its proper divisors (40047473375).

120142420113 is an equidigital number, since it uses as much as digits as its factorization.

120142420113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40047473374.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 120142420113 its reverse (311024241021), we get a palindrome (431166661134).

The spelling of 120142420113 in words is "one hundred twenty billion, one hundred forty-two million, four hundred twenty thousand, one hundred thirteen".