1201424201131 has 32 divisors (see below), whose sum is σ = 1507165470720. Its totient is φ = 930373360800.

The previous prime is 1201424201071. The next prime is 1201424201213. The reversal of 1201424201131 is 1311024241021.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201424201131 is a prime.

It is a super-2 number, since 2×1201424201131² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1201424001131) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 104293590 + ... + 104305108.

It is an arithmetic number, because the mean of its divisors is an integer number (47098920960).

Almost surely, 2^{1201424201131} is an apocalyptic number.

1201424201131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1201424201131 is a deficient number, since it is larger than the sum of its proper divisors (305741269589).

1201424201131 is a wasteful number, since it uses less digits than its factorization.

1201424201131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19815.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 1201424201131 its reverse (1311024241021), we get a palindrome (2512448442152).

The spelling of 1201424201131 in words is "one trillion, two hundred one billion, four hundred twenty-four million, two hundred one thousand, one hundred thirty-one".