12014352643 has 2 divisors, whose sum is σ = 12014352644. Its totient is φ = 12014352642.

The previous prime is 12014352613. The next prime is 12014352751. The reversal of 12014352643 is 34625341021.

It is a weak prime.

It is an emirp because it is prime and its reverse (34625341021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12014352643 - 2²¹ = 12012255491 is a prime.

It is a super-2 number, since 2×12014352643² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12014352613) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007176321 + 6007176322.

It is an arithmetic number, because the mean of its divisors is an integer number (6007176322).

Almost surely, 2^12014352643 is an apocalyptic number.

12014352643 is a deficient number, since it is larger than the sum of its proper divisors (1).

12014352643 is an equidigital number, since it uses as much as digits as its factorization.

12014352643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 12014352643 its reverse (34625341021), we get a palindrome (46639693664).

The spelling of 12014352643 in words is "twelve billion, fourteen million, three hundred fifty-two thousand, six hundred forty-three".