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120145535350153 = 1053259114070267
BaseRepresentation
bin11011010100010110001111…
…111101001011010110001001
3120202101210121221012211121021
4123110112033331023112021
5111221431024022201103
61103310032540312441
734210141240225435
oct3324261775132611
9522353557184537
10120145535350153
11353114875768a5
1211585014842721
1352068a1a2b891
1421951098b79c5
15dd53db2cabbd
hex6d458ff4b589

120145535350153 has 4 divisors (see below), whose sum is σ = 120145650473680. Its totient is φ = 120145420226628.

The previous prime is 120145535350129. The next prime is 120145535350193. The reversal of 120145535350153 is 351053535541021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120145535350153 - 225 = 120145501795721 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120145535350193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55981875 + ... + 58088392.

It is an arithmetic number, because the mean of its divisors is an integer number (30036412618420).

Almost surely, 2120145535350153 is an apocalyptic number.

It is an amenable number.

120145535350153 is a deficient number, since it is larger than the sum of its proper divisors (115123527).

120145535350153 is a wasteful number, since it uses less digits than its factorization.

120145535350153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115123526.

The product of its (nonzero) digits is 675000, while the sum is 43.

The spelling of 120145535350153 in words is "one hundred twenty trillion, one hundred forty-five billion, five hundred thirty-five million, three hundred fifty thousand, one hundred fifty-three".

Divisors: 1 1053259 114070267 120145535350153