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120145610041 is a prime number
BaseRepresentation
bin110111111100100111…
…1001000010100111001
3102111010011011100220221
41233321033020110321
53432024234010131
6131105533220041
711452214556322
oct1577117102471
9374104140827
10120145610041
1146a540790a6
121b350631621
13b43940a062
145b5a80b449
1531d2b69411
hex1bf93c8539

120145610041 has 2 divisors, whose sum is σ = 120145610042. Its totient is φ = 120145610040.

The previous prime is 120145610033. The next prime is 120145610047. The reversal of 120145610041 is 140016541021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119941005625 + 204604416 = 346325^2 + 14304^2 .

It is a cyclic number.

It is not a de Polignac number, because 120145610041 - 23 = 120145610033 is a prime.

It is a super-2 number, since 2×1201456100412 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120145609988 and 120145610015.

It is not a weakly prime, because it can be changed into another prime (120145610047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60072805020 + 60072805021.

It is an arithmetic number, because the mean of its divisors is an integer number (60072805021).

Almost surely, 2120145610041 is an apocalyptic number.

It is an amenable number.

120145610041 is a deficient number, since it is larger than the sum of its proper divisors (1).

120145610041 is an equidigital number, since it uses as much as digits as its factorization.

120145610041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960, while the sum is 25.

The spelling of 120145610041 in words is "one hundred twenty billion, one hundred forty-five million, six hundred ten thousand, forty-one".